Question

ayudaaaa ahí van 4 porfavor es para hoy ​

Answer 1

3. a) 2

$\sqrt{ \frac{ {2}^{2002} }{ {2}^{2001} } + \frac{ {2}^{2001} }{ {2}^{2000} } } = \sqrt{2 + 2} = \sqrt{4} = 2$

4. c) 8

$\sqrt{ {2}^{5} + {3}^{2} - {4}^{0} + {5}^{2} - {1}^{2} } = \sqrt{32 + 9 - 1 + 25 - 1} = \sqrt{64} = 8$

5. e) 9

$\sqrt{ {3}^{2} + {4}^{ 3} + {2}^{3} } = \sqrt{9 + 64 + 8} = \sqrt{81} = 9$

6. c) 8

$\sqrt{ {1}^{4} + {3}^{3} + {6}^{2} } = \sqrt{1 + 27 + 36} = \sqrt{64} = 8$