Question

Ayuda a resolver x/(x-3)≤x/(x+1)

Answer 1

                    $\dfrac{x}{x-3}\leq \dfrac{x}{x+1}\\ \\ \\ \dfrac{x}{x-3}- \dfrac{x}{x+1}\leq0\\ \\ \\ \dfrac{4x}{(x-3)(x+1)}\leq0\\ \\ \\ \dfrac{x}{(x-3)(x+1)}\leq0\\ \\ \\ x(x-3)(x+1)\leq0 \wedge x\notin\{-1,3\}\\ \\ \\ x\in (-\infty,-1]\cup [0,3] \wedge x\notin\{-1,3\}\\ \\ \\ \boxed{x\in (-\infty,-1)\cup [0,3)}$