Question

sistemas de ecuaciones lineales por el metodo de igualacion 4x-y=0 2x-3y=-5

Answer 1

4x-y=0 > x= y/4
2x-3y=-5 > x= (-5+3y)/2
y/4 = (-5+3y)/2
2y = 4(-5+3y)
2y = -20 +12y
-10y = - 20
y = 2
-------------------------
x=y/4
x= 2/4
x = 1/2

Answer 2

4x-y=0 > x= y/4
2x-3y=-5 > x= (-5+3y)/2
y/4 = (-5+3y)/2
2y = 4(-5+3y)
2y = -20 +12y
-10y = - 20
y = 2

x=y/4
x= 2/4
x = 1/2