Question

demuestra la funcion trigonometrica

cot^2∆÷1+cot^2∆=cos^2∆

Answer 1

cot^2x÷1+cot^2x=cosec^2x
(cos^2x/sen^2x) / (1+ cos^2x/sen^2x) = cosec^2x
(sen^2x+cos^2x) / sen^2x = cosec^2x
1/sen^2x = cosec^2x
cosec^2x = cosec^2x

asi seria, solo que al igualar es cosecante.