Question

Calcular la derivada de √x + 3x​

Answer 1

Respuesta:

$\frac{1}{\sqrt{x} }$

$\frac{1}{2\sqrt{x+3}}$

Explicación paso a paso:

$\frac{d}{dx} (\sqrt{x} +3)\\\frac{d}{dx} ({x})^-{\frac{1}{2}+\frac{d}{dx}(3)$

$-\frac{1}{2}x^{\frac{1-2}{2}} +0\\-\frac{1}{2}x^{-\frac{1}{2}}\\\frac{1}{x^{\frac{1}{2}}} \\\frac{1}{\sqrt{x} }$

$\frac{d}{dx}(\sqrt{x+3})\\\frac{d}{dx}(x+3)^{\frac{1}{2}}\\\frac{1}{2}(x+3)^{\frac{1-2}{2}}(\frac{d}{dx}(x+3))\\\frac{1}{2}(x+3)^{-\frac{1}{2}}(1)\\\frac{1}{2(x+3)^{\frac{1}{2}}}\\\frac{1}{2\sqrt{x+3}}$