• Asignatura: Matemáticas
  • Autor: kimberlyjhazim
  • hace 3 años

me lo pueden resolver por favor ​

Adjuntos:

Respuestas

Respuesta dada por: ANACF30
0

Respuesta:

a) \frac{2}{3}  +   \frac{3}{4} =  \frac{2(4) + 3(3)}{3(4)}  =  \frac{17}{12}

a) \frac{2}{3}  +  \frac{3}{4}  = m.c.d (12) =  \frac{4(2) + 3(3)}{12}  =  \frac{17}{12}

a) \frac{2}{3}  +   \frac{3}{4}  =  \frac{4(2)}{4(3)}  +  \frac{3(3)}{3(4)}  =  \frac{8}{12}  +  \frac{9}{12}  =  \frac{17}{12}

b) \frac{7}{5}  -  \frac{1}{2}  =  \frac{2(7) - 5(1)}{5(2)}  =  \frac{9}{10}

b) \frac{7}{5}  -  \frac{1}{2}  = m.c.d(10) =  \frac{2(7) - 5(1)}{10} =  \frac{9}{10}

b) \frac{7}{5}  -  \frac{1}{2}  =  \frac{2(7)}{2(5)}  -  \frac{5(1)}{5(2)}  =  \frac{14}{10}  -  \frac{5}{10}  =  \frac{9}{10}

c) \frac{4}{5}  \times  \frac{3}{4}  = \frac{4(3)}{5(4)}  =  \frac{12}{20}  =  \frac{3}{5}

c) \: simplificamos \:  \frac{4}{5}  \times  \frac{3}{4}  =  \frac{3}{5}

c) \frac{4}{5}  \times  \frac{3}{4}  =  \frac{3}{5}

d) \frac{6}{7}  \div  \frac{2}{5}  = \frac{6(5)}{7(2)}   =  \frac{30}{14}  =  \frac{15}{7}

d) \frac{6}{7}  \div  \frac{2}{5}  =  \frac{ \frac{6}{7} }{ \frac{2}{5} }  =  \frac{30}{14}  =  \frac{15}{7}

d) \frac{6}{7}  \times  \frac{2}{5} =  \frac{7}{6} \times  \frac{2}{5}  =  \frac{30}{14}  =  \frac{15}{7}

e) \frac{3}{4}  \div 6 =  \frac{ \frac{3}{4} }{\frac{6}{1} }  =  \frac{3}{24}  =  \frac{1}{8}

e) \frac{3}{4}  \div  \frac{6}{1}  =  \frac{4}{3}  \times  \frac{6}{1}  =  \frac{3}{24}  =  \frac{1}{8}

e) \frac{3}{4}  \div  \frac{6}{1}  =  \frac{ \frac{3}{4} }{ \frac{6}{1} }  =  \frac{3}{24}  =  \frac{1}{8}

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