Question

cuál es el cuadrado de cada binomio (4m5-t⁵n3)² y de (13w-12)²​

Answer 1

Respuesta:

${(4 {m}^{5} - {t}^{5} {n}^{3} )}^{2} = {(4 {m}^{5} )}^{2} + {( {t}^{5} {n}^{3} )}^{2} - 2 \times 4 {m}^{5} \times {t}^{5} {n}^{3} = 16 {m}^{10} + {t}^{10} {n}^{6} - 8 {m}^{5} {n}^{3} {t}^{5}$

${(13w - 12)}^{2} = {(13w)}^{2} + {12}^{2} - 2 \times 13w \times 12 = 169 {w}^{2} + 144 - 312w$

Explicación paso a paso:

${(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab$