Question

12. Resuelve:
(x+4)(x+3)-(x+2)(x+1) =
x(x-1)-(x-2)(x-3)+16
Pls

Answer 1

Respuesta:

x= 0

$\mathrm{Desarrollar\:}x\left(x-1\right)-\left(x-2\right)\left(x-3\right)+16:\quad4x+10$

$x\left(x-1\right)-\left(x-2\right)\left(x-3\right)+16$

$\mathrm{Expandir}\:x\left(x-1\right):\quad x^2-x$

$=x^2-x-\left(x-2\right)\left(x-3\right)+16$

$\mathrm{Expandir}\:-\left(x-2\right)\left(x-3\right):\quad-x^2+5x-6$

$=x^2-x-x^2+5x-6+16$

$\mathrm{Simplificar}\:x^2-x-x^2+5x-6+16:\quad4x+10$

$=4x+10$