Question

${4}^{2} \div {2}^{3} - ( {2}^{4} - {3}^{2} - {6}^{2} ) + {2}^{5} \times 3$
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Answer 1

Respuesta:

$\mathrm{4^2\div \:2^3-\left(2^4-3^2-6^2\right)+2^5\times \:3}$

$4^2\div \:2^3-\left(-29\right)+2^5\times \:3$

$16\div \:2^3-\left(-29\right)+2^5\times \:3$

$16\div \:8-\left(-29\right)+2^5\times \:3$

$2-\left(-29\right)+32\times \:3$

$2-\left(-29\right)+96$

$127$

Saludos...