calcular la masa molecular de los siguientes compuestos
a) H3BO3
b) AL2(SO4)3
c) H3PO3
d) H2CO3
e) HNO3
f) C6H1206
Doy 20 puntos pero aurita
Por favor es urgente
que p**** van a responder
Respuestas
H: 3 x 1 = 3 g/mol
B: 1 X 10.8 = 10.8 g/mol
O: 3 x 16 = 48 g/mol
``````````````````` `````````````
Mm = 61.8 g/mol
H2CO3
H: 2x 1 = 2 g/mol
C: 1 X 12 = 12 g/mol
O: 3 x 16 = 48 g/mol
``````````````````` `````````````
Mm = 62 g/mol
AL2(SO4)3
Al: 2 x 27 = 54 g/mol
S: 3 x 32 = 96 g/mol
O: 12 x 16 = 192 g/mol
````````````````````````````````
Mm = 342 g/mol
H3PO3
H: 3 x 1 = 3 g/mol
P: 1 x 31 = 31 g/mol
O: 3 x 16 = 48 g/mol
````````````````````````````````
Mm = 82 g/mol
HNO3
H: 1 x1 = 1 g/mol
N: 1 x 14 = 14 g/mol
O: 3 x 16 = 48 g/mol
``````````````````````````````
Mm = 63 g/mol
C6H12O6
C: 6 x 12 = 72 g/mol
H: 12 x 1 = 12 g/mol
O: 6 x 16 = 96 g/mol
``````````````````````````````````
Mm = 180 g/mol
Respuesta:
H3BO3
H: 3 x 1 = 3 g/mol
B: 1 X 10.8 = 10.8 g/mol
O: 3 x 16 = 48 g/mol
``````````````````` `````````````
Mm = 61.8 g/mol
H2CO3
H: 2x 1 = 2 g/mol
C: 1 X 12 = 12 g/mol
O: 3 x 16 = 48 g/mol
``````````````````` `````````````
Mm = 62 g/mol
AL2(SO4)3
Al: 2 x 27 = 54 g/mol
S: 3 x 32 = 96 g/mol
O: 12 x 16 = 192 g/mol
````````````````````````````````
Mm = 342 g/mol
H3PO3
H: 3 x 1 = 3 g/mol
P: 1 x 31 = 31 g/mol
O: 3 x 16 = 48 g/mol
````````````````````````````````
Mm = 82 g/mol
HNO3
H: 1 x1 = 1 g/mol
N: 1 x 14 = 14 g/mol
O: 3 x 16 = 48 g/mol
``````````````````````````````
Mm = 63 g/mol
C6H12O6
C: 6 x 12 = 72 g/mol
H: 12 x 1 = 12 g/mol
O: 6 x 16 = 96 g/mol
``````````````````````````````````
Mm = 180 g/mol
Explicación:
H3BO3
H: 3 x 1 = 3 g/mol
B: 1 X 10.8 = 10.8 g/mol
O: 3 x 16 = 48 g/mol
``````````````````` `````````````
Mm = 61.8 g/mol
H2CO3
H: 2x 1 = 2 g/mol
C: 1 X 12 = 12 g/mol
O: 3 x 16 = 48 g/mol
``````````````````` `````````````
Mm = 62 g/mol
AL2(SO4)3
Al: 2 x 27 = 54 g/mol
S: 3 x 32 = 96 g/mol
O: 12 x 16 = 192 g/mol
````````````````````````````````
Mm = 342 g/mol
H3PO3
H: 3 x 1 = 3 g/mol
P: 1 x 31 = 31 g/mol
O: 3 x 16 = 48 g/mol
````````````````````````````````
Mm = 82 g/mol
HNO3
H: 1 x1 = 1 g/mol
N: 1 x 14 = 14 g/mol
O: 3 x 16 = 48 g/mol
``````````````````````````````
Mm = 63 g/mol
C6H12O6
C: 6 x 12 = 72 g/mol
H: 12 x 1 = 12 g/mol
O: 6 x 16 = 96 g/mol
``````````````````````````````````
Mm = 180 g/mol