Question

^61+20×(-2)+6-(2+3×6)÷-10​

Answer 1

$61 + 20 \times ( - 2) - 6 - (2 + 3 \times 6) \div ( - 10)$

$61 - 40 - 6 - (2 + 18) \div ( - 10)$

$61 - 40 - 6 - 20 \div ( - 10)$

$61 - 40 - 6 + 2$

$17$