Question

3{[(x-2)+4x]-(x-3)}=4-(x-12)

Answer 1

3{[(x-2)+4x]-(x-3)}=4-(x-12)

3{[x-2+4x]-x+3}=4-x+12

3{5x-2-x+3}=-x+16

3{4x+1}=-x+16

12x + 3 = -x +16

12x+x= 16-3

13x = 13

x = 1

Answer 2

Respuesta:

Explicación paso a paso:

3{[(x-2)+4x]-(x-3)}=4-(x-12)

3{[x-2+4x]-x+3}=4-x+12

3{5x-2-x+3}=-x+16

3{4x+1}=-x+16

12x + 3 = -x +16

12x+x= 16-3

13x = 13

x = 1