Question

The perimeter of a rectangle field is 118m. If the length of the rectangle is
7m less than twice the width, what is the length of the field?​

Answer 1

OK, we’ve got a rectangular field with a perimeter of 118m; we’re asked to find the length of the field if it is 7m less than twice the width of the field.

Perimeter = 118m

2L + 2W = 118m

Length = (2W - 7m) We want to express L in terms of W, so that we are working with

one unknown, W.

2(2W - 7m) + 2W = 118m

4W - 14m + 2W = 118m

6W - 14m = 118m

6W = 118m + 14m

6W = 132m

W = 132m ÷ 6

W = 22m

∴ L = 2(22m) - 7m

L = 44m - 7m

L = 37m

Proof:

2L + 2W = 118m

2(37m) + 2(22m) = 118m

74m + 44m = 118m

118m = 118m

Proved: The field is 37m long and 22m wide