Question

Si x +y+z= 24 y x sobre 2 = y sobre 6= z sobre 8 determina el valor de x, de y, de z

Answer 1

Tienes los siguiente:
x/2 = y/6
6x/2 = y = 3x

x/2 = z/8
8x/2 = z = 4x

x + y + z = 24
x + 3x + 4x = 24
8x = 24
x = 24/8 = 3

y + z = 24 - x = 24 - 3 = 21

y/6 = z/8
8y/6 = z
4y/3 = z

y + z = 21
y + 4y/3 = 21
3(y + 4y/3) = 3(21)  
3y + 4y = 63
7y = 63
y = 63/7 = 9
z = 21 - y = 21 - 9 = 12

x = 3 ; y = 9 ; z = 12

Saludos!