calacula la composision porcentual de cada elemento que forma una molecula de acido sulfurico H2SO4 HNO3 y Na2SO4
Respuestas
Respuesta dada por:
9
H2SO4
Mm H: 2 x 1 = 2 g/mol
S: 1 x 32 g = 32 g/mol
O: 4 x 16 = 64 g/mol
````````````````````````````````
Mm = 98 g/mol
H
98 g ----- 100 %
2 g ----- X
x = 2.04 %
S:
98 g ----- 100 %
32 g ----- X
x = 32.65 %
O:
98 g ----- 100 %
64 g ----- X
x =65.30 %
HNO3
Mm H: 1 x 1 = 1 g/mol
N: 1 x 14 g = 32 g/mol
O: 3 x 16 = 48 g/mol
````````````````````````````````
Mm = 63 g/mol
H:
63 g ----- 100 %
1 g ----- X
x = 1.58 %
N:
63 g ----- 100 %
14 g ----- X
x = 22.22%
O:
63 g ----- 100 %
48 g ----- X
x = 76.19%
Na2SO4
Mm Na: 2 x 23 = 46 g/mol
S: 1 x 32 = 32 g/mol
O: 4 x 16 = 64 g/mol
``````````````````````````````````````
Mm = 142 g/mol
Na:
142 g ----- 100 %
46 g ----- X
x = 32.39 %
S:
142 g ----- 100 %
32 g ----- X
x = 22.53 %
O:
142 g ----- 100 %
64 g ----- X
x = 45.07 %
Mm H: 2 x 1 = 2 g/mol
S: 1 x 32 g = 32 g/mol
O: 4 x 16 = 64 g/mol
````````````````````````````````
Mm = 98 g/mol
H
98 g ----- 100 %
2 g ----- X
x = 2.04 %
S:
98 g ----- 100 %
32 g ----- X
x = 32.65 %
O:
98 g ----- 100 %
64 g ----- X
x =65.30 %
HNO3
Mm H: 1 x 1 = 1 g/mol
N: 1 x 14 g = 32 g/mol
O: 3 x 16 = 48 g/mol
````````````````````````````````
Mm = 63 g/mol
H:
63 g ----- 100 %
1 g ----- X
x = 1.58 %
N:
63 g ----- 100 %
14 g ----- X
x = 22.22%
O:
63 g ----- 100 %
48 g ----- X
x = 76.19%
Na2SO4
Mm Na: 2 x 23 = 46 g/mol
S: 1 x 32 = 32 g/mol
O: 4 x 16 = 64 g/mol
``````````````````````````````````````
Mm = 142 g/mol
Na:
142 g ----- 100 %
46 g ----- X
x = 32.39 %
S:
142 g ----- 100 %
32 g ----- X
x = 22.53 %
O:
142 g ----- 100 %
64 g ----- X
x = 45.07 %
WANDERLAND:
MUCHAS GRASIAS POR TOMARTE EL TIEMPO PARA ALLUDARME
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