Question

razones trigonometricas
sen20.sec70+2cos10.csc80+3tg40.tg50

Answer 1

formulas: sen(90-x) = cos x, cos(90-x) = sen x, tg(90-x) = ctg x, sec x = 1/cos x, csc x = 1/sin x, tg x * ctg x = 1 sen 20 = sen(90-70) = cos 70, cos 10 = cos(90-80)= sen 80 tg 40 = tg(90-50) = ctg 50 asi esto es cos70 * 1/cos70 +2sen80 * 1/sen80 +3ctg 50 tg50 = 1+2+3=6