Question

hallar la base y altura de un triangulo isosceles de area minima circunscrito a la elipse: x²/a²+ y²/ b² =1 , y cuya base sea paralela al eje "x"

Answer 1

a² ? x² + y² ? b²d(x,y) = e-(x²+y²)dA = r·dr·d?dM = d(x,y)·dAx² + y² = r² (cambio)M = ?e-(x² + y²)·dA = ?e-r²·r·dr·d? =?/2   b
?d? · ?e-r²·r·dr = 
0   a