2x²+3y+4+4x²+2y+5=

3y+2+3y+2+3y+2+3y+2=

3y+4+4y+3+5y+8+4y+3=

2x²+3y+5x²+8y+4x²+5y=

6x²+3+9x²+5+10x²+8=

6y³+4x²-3+8-2y³+x² ​

Respuestas

Respuesta dada por: IvyChen
15

Respuesta:

2 {x}^{2}  + 3y + 4 +  {4x}^{2}  + 2y + 5 =  {6x}^{2}  + 5y + 9

3y + 2 + 3y + 2 + 3y + 2 + 3y + 2 = 12y + 8

3y + 4 + 4y + 3 + 5y + 8 + 4y + 3 = 16y + 18

 {2x}^{2}  + 3y +  {5x }^{2}  + 8y +  {4x}^{2}  + 5y =  {11x}^{2} +  16y

 {6x}^{2}  + 3 +  {9x}^{2}  + 5 +  {10x}^{2}  + 8 =  {25x}^{2}  + 16

 {6y}^{3}  +  {4x}^{2}  - 3 + 8 -  {2y}^{3}  +  {x}^{2}  = 4 {y}^{3}  + 5 {x}^{2}  + 5

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