• Asignatura: Matemáticas
  • Autor: sebasmendoza200
  • hace 4 años

resolver las siguientes ecuaciones con su respectiva comprobación

Adjuntos:

Respuestas

Respuesta dada por: sanju0617anjo
3

Respuesta:

1.

x + 6 = 20 \\ x = 20 - 6 \\ x = 14 \\  \\ x + 6 = 20 \\ 14 + 6 = 20 \\ 20 = 20

2.

x + 13 = 18 \\ x = 18 - 13 \\ x = 5 \\  \\ x + 13 = 18 \\ 5 + 13 = 18 \\ 18 = 18

3.

x - 10 = 19 \\ x = 19 + 10 \\ x = 29 \\  x - 10 = 19 \\ 29 - 10 = 19 \\ 19 = 19

4.

x - 5 = 47 \\ x = 47  + 5 \\ x = 52\\ x - 5 = 47 \\ 52 - 5 = 47 \\ 47 = 47

5.

 \frac{x}{9}  = 25 \\ x = 25 \times 9 \\ x = 225 \\  \frac{x}{9}  = 25 \\  \frac{225}{9}  = 25 \\ 25 = 25

6.

 \frac{x}{12}  = 36 \\ x = 36 \times 12 \\ x = 432 \\  \frac{x}{12}  = 36 \\  \frac{432}{12}  = 36 \\ 36 = 36

7.

6x + 7 = 36 - 4x \\ 6x + 4x = 36 - 7 \\ 10x = 29 \\ x = \frac{29}{10}  \\ 6x + 7 = 36 - 4x \\ 6( \frac{29}{10} ) + 7 = 36 - 4( \frac{29}{10} ) \\  \frac{87}{5}  + 7 = 36 -  \frac{58}{5}  \\  \frac{122}{5}  =  \frac{122}{5}

8.

8x - 13 = 24 + 7x \\ 8x - 7x = 24 + 13 \\ x = 37 \\ 8x - 13 = 24 + 7x \\ 8(37) - 13 = 24 + 7(37) \\ 296 - 13 = 24  + 259 \\ 283 = 283

9.

3(x + 2) - 5(x + 3) = x + 5 \\ 3x + 6 - 5x  - 15 = x + 5 \\ 3x - 5x - x = 5 - 6 + 15 \\  - 3x = 14 \\ x =  -  \frac{14}{3}  \\ 3(x + 2) - (x + 3) = x + 5 \\ 3( -  \frac{14}{3}  + 2) - 5( -  \frac{14}{3}  + 3) =  -  \frac{14}{3}  + 5 \\ 3( -  \frac{8}{3} ) - 5( -  \frac{5}{3} ) =  \frac{1}{3}  \\  - 8 - ( -  \frac{25}{3} ) =  \frac{1}{3}  \\  - 8 +  \frac{25}{3}  =  \frac{1}{3}  \\  \frac{1}{3}  =  \frac{1}{3}

10.

7(x - 3) +  8(x - 5) = x - 4 \\ 7x - 21 + 8x - 40 = x - 4 \\ 7x + 8x - x =  - 4 + 21 + 40 \\ 14x = 57 \\ x =  \frac{57}{14}  \\ 7(x - 3) + 8(x - 5) = x - 4 \\ 7( \frac{57}{14}  - 3) + 8( \frac{57}{14 }  - 5) =  \frac{57}{14}  - 4 \\ 7( \frac{15}{14} ) + 8( -  \frac{13}{14} ) =  \frac{1}{14}  \\  \frac{15}{2}  + ( -  \frac{52}{7} ) =  \frac{1}{14}  \\  \frac{15}{2}  -  \frac{52}{7}  =  \frac{1}{14}  \\  \frac{1}{14}  =  \frac{1}{14}

espero te sirva mi aporte elije la mejor respuesta y califica gracias

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