Question

k = 8tg45º+4tg37º+3tg53

Answer 1

Se sabe por ángulos notables que:

tg45° = 1

tg 37° = 3/4

tg 53° = 4/3

Solo reemplazamos:

k = 8tg45º+4tg37º+3tg53°

k = 8*1 + 4*(3/4) + 3*(4/3)

k = 8 + 4 + 3

k  = 15