Question

si: senθ=√7/4 calcular :E=3secθ - √7 tgθ

Answer 1

C.O/H=SENβ=√7/4

C.O²+C.A²=H²
(√7)²+C.A²=4²
7+C.A²=16
C.A²=16-7
C.A=√9
C.A=3

ENTONCES:
E=3secβ-√7tgβ
E=3×(H/C.A)-√7 ×(C.O/C.A)
E=3×(4/3)-√7×(√7/3)
E=4-7/3
E=5/3