Question

II.
Resuelve las siguientes ecuaciones incompletas
1. x²-9=0
2. 2x² - 32 = 0
3. x²+ 2x = 0
4. 6x²+ 12x = 0
5. 3x² + 9x = 0
ayúdenme por favor me urge ​

Answer 1

x²-9 = 0

(x+3)(x -3) = 0

x + 3 =     x - 3 = 0

x = -3      x = +3

CS = (-3; 3)

2x² - 32 = 0

2x² = 32

x² = 32/2

x² = 16

$\sqrt{x^{2} } = \sqrt{16}$

x = ± 4

x²+ 2x = 0

x(x + 2) = 0

x = 0    x + 2 = 0

x =  0       x = -2

CS = ( -2 ; 0 )

6x²+ 12x = 0

2x(x +6) = 0

2x = 0          x + 6 = 0

x = 0/2        x = -6

x = 0        

CS = ( -6 ;  0 )

Eternamente axllxa

Answer 2

Respuesta:

5. 3x² + 9x = 0

Soluciones: x=0, X= -3

Explicación paso a paso:

3x (x+3)=0

x+3-3=0-3

x+3=0

x=0

x= -3

xd