Question

áreas de regiones de triángulos
porfavor sólo personas responsables. ​

Answer 1

Explicación paso a paso:

AREA DEL TRIANGULO

$\boxed{A = \frac{base \times altura}{2} }$

$05. \\ base = 16 \sqrt{2} \\ altura = 6 \sqrt{2} \\ \\ A = \frac{16 \sqrt{2} \times 6 \sqrt{2} }{2} \\ A = \frac{16 \times 2 \times 6}{2} \\A = \frac{192 }{2} \\ \boxed{A = 96}$

$06. \\ base = 8 \\ altura = 6 \\ \\ A = \frac{8 \times 6}{2} \\ A = \frac{48 }{2} \\ \boxed{A = 24}$

$07. \\ base = 12 \\ altura = 5 \\ \\ A = \frac{12 \times 5 }{2} \\ A = \frac{60 }{2} \\ \boxed{A = 30}$

$08. \\ lado \: (l) = 16 \\ \\ A = \frac{ {l}^{2} \sqrt{3} }{4} \\ A = \frac{ {16}^{2} \sqrt{3} }{4}\\ A = \frac{256 \sqrt{3} }{4} \\ \boxed{A = 64 \sqrt{3}} \: \:o\: \:\boxed{A=110.85}$

$09. \\ lado \: (l) = 4 \\ \\ A = \frac{ {l}^{2} \sqrt{3} }{4} \\ A = \frac{ {4}^{2} \sqrt{3} }{4}\\ A = \frac{16 \sqrt{3} }{4} \\ \boxed{A = 4\sqrt{3}}\: \:o\:\: \boxed{A=6.9}$