Question

AYUDAME A RESOLVER PORFAVOR

a) 3(x+-2) =-5(x+10
b) 4(x+3)-11(x-7)=4(5x+2)
c) 12+x+1=4(x+1)
d) 4a-6-7a+14=21-15a-7+3a​

Answer 1

Respuesta:

$3x - 6 = - 5x - 50\\3x +5x = - 50 + 6\\8x = - 44\\x = - 44 / 8\\x = - 5.5\\\\4x + 12 - 11x +77 = 20x + 8\\4x - 11x - 20x = 8 -12 - 77\\- 27x = - 81\\x= - 82 / - 27\\x= 3\\\\12 +x + 1 = 4x +4\\x - 4x = 4 - 12 - 1\\- 3x = - 9\\x = - 9 / - 3\\x =3\\\\4a - 6 - 7a + 14 = 21 - 15a - 7 + 3a4a - 7a + 15a- 3a = 21 - 7 + 6 - 14\\9x = 6\\x = 6/ 9\\x = 0.66666$

Explicación paso a paso: