Question

Reduce L= (sen50°+cos50°)/(cos5°)

Answer 1

Hola!

L= (sen50°+cos50°)/(cos5°)

sen50° + cos50°

sen50° + sen40° = 2 sen(50°+ 40°)/2 cos(50° - 40°)/2

sen50° + sen40° = 2 sen45° cos5°

sen50° + sen40° = 2(√2/2) cos5°

sen50° + sen40° = √2 cos5°

Espero te sirva! =3