Question

Ayudadme es para mañana es de mates ​

Answer 1

¡Hola amig@!

Bueno aquí las respuestas :

A)

$\frac{6\left(-1\right)^3-3^2\cdot \:2}{\sqrt{6^2}}$

$\frac{-24}{\sqrt{6^2}}$

$\frac{-24}{6}$

= -4

B)

$\left(4-3\right)^2-5\cdot \left(2^2-7\right)$

$1^2-5\left(2^2-7\right)$

$1^2-5\left(-3\right)$

$1-5\left(-3\right)$

$1-\left(-15\right)$

= 16

C)

$\left[\left(\sqrt{9}-\sqrt{25}\right)^4\right]$

$\left(\sqrt{9}-\sqrt{25}\right)^4$

$\left(3-5\right)^4$

$\left(-2\right)^4$

$2^4$

= 16

D)

$5^2\cdot \left(\sqrt{64}+8\div 2\right)$

$5^2\left(\frac{\sqrt{64}+8}{2}\right)$

$5^2\cdot \frac{\sqrt{64}+8}{2}$

$5^2\cdot \:8$

$25\cdot \:8$

=200

E)

$\left(9^2-7^2\right)\div \sqrt{64}$

$\frac{9^2-7^2}{\sqrt{64}}$

$\frac{32}{\sqrt{64}}$

$\frac{2^5}{2^3}$

$2^2$

=4

F)

$\left(-\sqrt{49}+3^4\div 3^2\right)^5$

$\left(\frac{-\sqrt{49}+3^4}{3^2}\right)^5$

$\frac{\left(-\sqrt{49}+3^4\right)^5}{\left(3^2\right)^5}$

$\frac{\left(-\sqrt{49}+3^4\right)^5}{59049}$

$\frac{\left(-\sqrt{49}+81\right)^5}{59049}$

=$\frac{74^5}{59049}$