Question

Hallar :

(4u)²+(x)²=41​

Answer 1

Respuesta:

♫HOLA♫

Solución:

$(4u)^{2} +(x)^{2} =41\\\\16u^{2} +x^{2} = 41$

$x = \sqrt{41 -16u^{2} } \\\\x = -\sqrt{41 -16u^{2} }$                   $u = \frac{\sqrt{41-x^{2} } }{4} \\\\u=-\frac{\sqrt{41-x^{2} } }{4}$

Explicación paso a paso:

Hola amigo(a) espero que te ayude :) ♫