Question

(x+11)(x-11)=
(x-7)(x+7)=
(a+1)(a-1)=
(b+20)(b-20)=
(x+9)(x-9)=
(w-8)(w+8)=
(m+15)(m-15)=
(z+100)(Z-100)=

Answer 1

(x+11)(x-11)= x² - 121

(x-7)(x+7)=  x² - 49

(a+1)(a-1)=  a² - 1

(b+20)(b-20)=  b² - 400

(x+9)(x-9)=  x² - 81

(w-8)(w+8)=  w² - 64

(m+15)(m-15)=  m² - 225

(z+100)(Z-100)= z² - 10000

espero que te sirva los ejercicios.   :)

Answer 2

Explicación paso a paso:

${x}^{2} - 11x + 11x - 121 = {x}^{2} - 121$

${x}^{2} + 7x - 7x - 49 = {x}^{2} - 49$

${a}^{2} - a + a - 1 = {a}^{2} - 1$

${b}^{2} - 20b + 20b - 400 = {b}^{2} - 400$

${x}^{2} - 9x + 9x - 81 = {x}^{2} - 81$

${w}^{2} + 8w - 8w - 64 = {w}^{2} - 64$

${m}^{2} - 15m + 15m - 225 = {m}^{2} - 225$

${z}^{2} - 100z + 100z - 10000 = {z}^{2} - 10000$