Question

Derivada Implicita de: x^2cosy+sen2y=xy

Answer 1

Respuesta:

$\frac{d}{dx}\left(y\right)=\frac{y-2x\cos \left(y\right)}{-x^2\sin \left(y\right)+2\cos \left(2y\right)-x}$

Explicación:

$x^2\cos \left(y\right)+\sin \left(2y\right)=xy$

$2xcos(y)-x^{2} sin(y)\frac{d}{dx}\left(y\right)+cos(2y)$

$2\frac{d}{dx}\left(y\right)=y+x\frac{d}{dx}\left(y\right)$

$\frac{d}{dx}\left(y\right): \frac{d}{dx}\left(y\right)=\frac{y-2x\cos \left(y\right)}{-x^2\sin \left(y\right)+2\cos \left(2y\right)-x}$

$\frac{d}{dx}\left(y\right)=\frac{y-2x\cos \left(y\right)}{-x^2\sin \left(y\right)+2\cos \left(2y\right)-x}$