Question

Ayudenme porfavor necesito las respuestas:(

Answer 1

Respuesta:

$(6 {a}^{2} + 2ab - 8 {b}^{2} )(3a - 2b) \\ 18 {a}^{3}+ 6 {a}^{2} b - 24a {b}^{2} - 12 {a}^{2} b - 4a {b}^{2} + 16 {b}^{3} \\ 18 {a}^{3} - 6 {a}^{2} b - 28a {b}^{2} + 16 {b}^{3}$

$( - 3 {x}^{4} + 2 {x}^{3} - 4 {x}^{2} + 2x - 1)( {x}^{2} - 5x + 3) \\ - 3 {x}^{6} + 2 {x}^{5} - 4 {x}^{4} + 2 {x}^{3} - {x}^{2} + 15 {x}^{5} - 10 {x}^{4} + 20 {x}^{3} - 10 {x}^{2} + 5x - 9 {x}^{4} + 6 {x}^{3} - 12 {x}^{2} + 6x - 3 \\ - 3 {x}^{6} + 17 {x}^{5} - 23 {x}^{4} + 28 {x}^{3} - 23 {x}^{2} + 11x - 3$

$( \frac{3}{4} {m}^{3} - \frac{2}{5} {m}^{2} n + \frac{1}{3} m {n}^{2} + \frac{1}{2} {n}^{3} )(2m + 3n) \\ \frac{3}{2} {m}^{4} - \frac{4}{5} {m}^{3} n + \frac{2}{3} {m}^{2} {n}^{2} + 1m {n}^{3} + \frac{9}{4} {m}^{3} n - \frac{6}{5} {m}^{2} {n}^{2} + 1m {n}^{3} + \frac{3}{2} {n}^{4} \\ \frac{3}{2} {m}^{4} + \frac{29}{20} {m}^{3} n - \frac{8}{15} {m}^{2} {n}^{2} + 2m {n}^{3} + \frac{3}{2} {n}^{4}$