Question

Si n(P(A))=32 , n(P(B))=8 Y n(P(C))=4 calcula.

a. n(A) + n(B) + n(C)

b. [n(A )+ n(B)] .[ n(C)]

c. n(A) - n(B )- n(C)

d. [n(A) - n(C)] . [n(B)]

Answer 1

a. 32+8+4=44

b. (32+8)×4=160

c. 32-8-4=20

d. (32-4)×8=224

Answer 2

Respuesta:

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Explicación paso a paso: