Question

Ayúdenme porfa. Os adjunto ña foto

Answer 1

Respuesta:

$\frac{2^4*2^3*2^7}{2^5*2^6}=\frac{2^{4+3+7}}{2^{5+6}}=\frac{2^{14}}{2^{11}}=2^{14-11}=2^3$

$\frac{x^3*(x^4)^2}{x^6*x*x^2}=\frac{x^3*x^{4*2}}{x^{6+1+2}}=\frac{x^3*x^{8}}{x^{9}}=\frac{x^{3+8}}{x^9}=\frac{x^{11}}{x^9}=x^{11-9}=x^2$

$\frac{(-5)^3*((-5)^2)^5}{((-5)^3)^4*(-5)}=\frac{(-5)^3*(-5)^{10}}{(-5)^{12}*(-5)}=\frac{(-5)^{13}}{(-5)^{13}}=(-5)^{13-13}=(-5)^{0}=1$