Question

How many moles in 709.5g of manganese (IV) dichromate?

Answer 1

Respuesta:

2.952645 moles

Explicación:

709.5×1

709.5÷240.29= 2.9526

240.29 gr/mol Cr2MgO7

$\frac{1mol }{240.29gr} = \frac{x}{709.5}$