Question

calcula la diferencial y=2x⁴-5x²+2 para x=2 ∆x=0,2

Answer 1

$\Delta y = f(x_0+\Delta x) - f(x_0)\\ \\ \Delta y = 2(2+0.2)^4-5(2+0.2)^2+2 - [2(2^4)-5(2)^2+2]\\ \\ \Delta y =10.6512$