Question

resuelve: x²-7x-13=0

Answer 1

Hola , espero que te sirva :D

$x^{2} - 7x - 13 = 0\\\\\\x =\dfrac{-(-7)+-\sqrt{(-7)^{2}-4.1.(-13) } }{2.1} \\\\\\x = \dfrac{7+-\sqrt{49+52} }{2} \\\\\\x=\dfrac{7+-\sqrt{101} }{2} \\\\\\x=\dfrac{7+\sqrt{101} }{2}\\\\\\x=\dfrac{7-\sqrt{101} }{2}\\\\\\x_{1} = \dfrac{7-\sqrt{101} }{2} , x_{2} = \dfrac{7+\sqrt{101} }{2}$