Question

$4a ^{2} + 24a= 0$

Answer 1

$\mathrm{Para\:}\quad a=4,\:b=24,\:c=0:\quad a_{0,\:1}=\frac{-\left(24\right)\pm \sqrt{\left(24\right)^2-4\left(4\right)\left(0\right)}}{2\left(4\right)}$
$a=\frac{-24+\sqrt{24^2-4\cdot \:0\cdot \:4}}{2\cdot \:4}=0$
$a=\frac{-24-\sqrt{24^2-4\cdot \:0\cdot \:4}}{2\cdot \:4}=-6$
Nos da:
$a=0,\:a=-6$