Paso 3. Practico.porfabor selos pedo de carida ayudenme aaaaaaaaaaaayudenmen
Resuelve las siguientes potenciaciones de números racionales:
1. (4/7)2 x (4/7)
3
=
2. (2/5)3 x (-2/5)
4 =
3. (6/7)2
. (6/7)
4
. (6/7)
5 =
4. (-3/2)2 ÷ (9/2)-1 x (-5/2)0 =
5. (12/2)1 + (3/2)2 =
6. (-1/8)2
(3/5)0
(-2/4)1
(-3/2)-1 =
7. ((((-3/7)3
)
4
)
1
)
5 =
8. (((((3/8)8
)
5
)
10)
2
)
0 =
9. {(2/7)
2
(2/7)3
(2/7)
6
} ÷ {(2/7)1
(2/17)3
(-2/7)
2
} =
10. (4/9)2 + (6/7)-1 =
11. [(-3/2)
0
(1/4)2
] – [(4/5)1
(3/8)-1
] =
12. -[(3/5)
2 x (7/9)
3 x (5/11)
0
] =
13. { - [ 3/2 x 9/8]2 – ½} =
14. –{(-3/9)-1
(8/3)2
(1/5)} =
15. –{–[(2/5)2
(-3/11)3
]} =
16. { -[(1/4)1
(2/13)4
(-2/7)2
]} =
17. {¾ .(1/5)
3
} + (2/3)2 =
Respuestas
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El valor de cada expresión usando las propiedades de potenciación correspondientes son :
a) (7/9)^3 = 343/729
b) (-7/3)^4=2401/81
c) (-6/2)^5= -243
d) (3/6)^2= 1/4
e) (2/6)*(2/6)^0*(2/6)^2*(2/6)^3=1/729
f) (-3/9)*(-3/9)^-1 =1
g) [(-7/5)^2]^3 = 7^6/5^6 = 117649/15625
h) [(3/7)^3]^2= 3^6/7^6= 729/117649
i) [(1/3)^2]^3*(1/3)^2 = (1/3)^8
j) [(5/7)^2]^2 * (5/7)^2 = (5/7)^6
k) (3/8)^7÷(3/8)^2=(3/8)^5
l) ( 4/3)^4÷(4/3)^2= (4/3)^2 = 4^2/3^2=16/9
m) [(-2/4)^4*(5/3)^-4]/[(-2/4)*(3/5)] = 81/10000
n) [(-3/4)^3 ÷ (-3/4)^5]^4=( 4/3)^8
a. ( 7/9)^3= 7^3/9^3= 343/729
b. (-7/3) elevado a la cuarta:
(-7/3)⁴ = 7⁴/3⁴ = 2401/81
c. (-6/2) elevado a la quinta :
(-6/2)^5 = (-3)^5 = -243
d. (3/6) elevado al cuadrado :
(3/6)² = (1/2)² = 1/4
e. Dos sextos por dos sextos elevado a cero por dos sextos elevado al cuadrado por dos sextos elevado al cubo :
( 2/6)* (2/6)⁰* (2/6)² *(2/6)³ = ( 2/6)⁶ = ( 1/3 )⁶ = 1⁶ /3⁶ = 1/729
f. Menos tres novenos por menos tres novenos elevado menos uno:
(-3/9) * (-3/9)⁻¹ = ( -1/3)* ( - 9/3)¹ = (-1/3)*(-3)¹ = 1
g. [(-7/5)^2]^3 = ( -7/5)^6= 7^6/5^6 = 117649/15625
h. [(3/7)^3]^2=(3/7)^6= 3^6/7^6= 729/117649
i. [(1/3)^2]^3*(1/3)^2 =(1/3)^6*(1/3)^2= (1/3)^8
j. [(5/7)²]² por (5/7) elevado al cuadrado :
(5/7)⁴* (5/7)² = (5/7)⁶ = 5⁶/7⁶ = 15625/117649
k. (3/8) elevado a la séptima dividido (3/8) elevado al cuadrado :
(3/8)⁷ ÷ (3/8)² = ( 3/8 )⁵
l. ( 4/3)^4÷(4/3)^2=16/9
m. [(-2/4)^4*(5/3)^-4]/[(-2/4)*(3/5)] =
= (-2/4)^4*(3/5)^4 = (-1/2)^4*(3/5)^4= 1/16*81/625
= 81/10000
n . [(-3/4)³ ÷ (-3/4)⁵]⁴ = [ ( -3/4)⁻²]⁴ = [ ( - 4/3)²]⁴ = ( - 4/3)⁸ = (4/3)⁸
Respuesta:
Explicación paso a paso:
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