Question

eso es la pregunta plis

Answer 1

Respuesta:

Espero que te sirva :D

Explicación paso a paso :

1)

$x^{2} - 5x + 6 = 0 \\\\x^{2} - 2x - 3x + 6 = 0\\\\x . ( x - 2 ) - 3 ( x-2 ) = 0\\\\(x-2) . ( x--3) = 0\\\\x - 2 = 0\\x-3 = 0\\\\x = 2\\x = 3\\\\x_{1} = 2 , x_{2} = 3$

2)

$x^{2} + x - 6 = 0\\\\x^{2} + 3x - 2x - 6 = 0\\\\x.(x+3) - 2 ( x+3) = 0\\\\(x + 3 ) . ( x - 2 ) = 0\\\\(x+3).(x+2) = 0\\\\x + 3 = 0\\x - 2 = 0\\\\x_{1} = -3 , x_{2} = 2$