Question

#02 me ayudan porfas mate...

Answer 1

Respuesta:

.-. no entiendo

Explicación paso a paso:

Answer 2

Recuerda:

${(x + y)}^{3} = {x}^{3} + {y}^{3} + 3xy(x + y)$

...

${x}^{2} + \frac{1}{ {x}^{2} } = 3$

${( {x}^{2} + \frac{1}{ {x}^{2} } ) }^{3} = {3}^{3}$

${x}^{6} + \frac{1}{ {x}^{6} } + 3( {x}^{2} )( \frac{1}{ {x}^{2} } )( {x}^{2} + \frac{1}{ {x}^{2} } ) = 27$

${x}^{6} + \frac{1}{ {x}^{6} } + 3(1)(3) = 27$

${x}^{6} + \frac{1}{ {x}^{6} } = 27 - 9$

${x}^{6} + \frac{1}{ {x}^{6} } = 18$