resuelve estas ecuaciones y comprueba que las soluciones halladas sean las correctas.
A. x/2 + 3/5 = 4/3 - x/6
B. 2x-1/5 = x+4/3 - 7/2
C. x/3 + x/5 + 1 = 3x/4 - 1/2
D. 2x- 1-3x/10 - 2/3 =2(x-3)+ 1/5
ayuda x faaaaaaa :(
Respuestas
Respuesta dada por:
123
En todas coloquemos las incógnitas al lado izquierdo y los números al lado derecho
A. x/2 + 3/5 = 4/3 - x/6
x/2 + x/6 = 4/3 - 3/5
4x/6 = 11/15
2x/3 = 11/15
x = 11 / 10
Comprobación:
(11 / 10) / 2 + 3/5 = 4/3 - (11 / 10)/6
11/20 + 3/5 = 4/3 - 11/60
23/20 = 23/20
B. 2x-1/5 = x+4/3 - 7/2
2x - x = 4/3 - 7/2 + 1/5
x = -59/30
C. x/3 + x/5 + 1 = 3x/4 - 1/2
x/3 + x/5 - 3x/4 = -1/2 - 1
-13x/60 = -3/2
x = 90/13
D. 2x- 1-3x/10 - 2/3 =2(x-3)+ 1/5
2x - 3x/10 - 2x = -6 + 1/5 + 1 + 2/3
- 3x/10 = -62/15
x = 124/9
A. x/2 + 3/5 = 4/3 - x/6
x/2 + x/6 = 4/3 - 3/5
4x/6 = 11/15
2x/3 = 11/15
x = 11 / 10
Comprobación:
(11 / 10) / 2 + 3/5 = 4/3 - (11 / 10)/6
11/20 + 3/5 = 4/3 - 11/60
23/20 = 23/20
B. 2x-1/5 = x+4/3 - 7/2
2x - x = 4/3 - 7/2 + 1/5
x = -59/30
C. x/3 + x/5 + 1 = 3x/4 - 1/2
x/3 + x/5 - 3x/4 = -1/2 - 1
-13x/60 = -3/2
x = 90/13
D. 2x- 1-3x/10 - 2/3 =2(x-3)+ 1/5
2x - 3x/10 - 2x = -6 + 1/5 + 1 + 2/3
- 3x/10 = -62/15
x = 124/9
Respuesta dada por:
74
Hola
![A) \\ \frac{x}{2}+ \frac{3}{5}= \frac{4}{3} - \frac{x}{6} \\ \\ \frac{x}{2}+ \frac{x}{6}= \frac{4}{3}- \frac{3}{5} \\ \\ \frac{8x}{12}= \frac{20-9}{15} \\ \\ \boxed{x= \frac{11}{10} }\\ \\ A) \\ \frac{x}{2}+ \frac{3}{5}= \frac{4}{3} - \frac{x}{6} \\ \\ \frac{x}{2}+ \frac{x}{6}= \frac{4}{3}- \frac{3}{5} \\ \\ \frac{8x}{12}= \frac{20-9}{15} \\ \\ \boxed{x= \frac{11}{10} }\\ \\](https://tex.z-dn.net/?f=A%29++%5C%5C++%5Cfrac%7Bx%7D%7B2%7D%2B++%5Cfrac%7B3%7D%7B5%7D%3D++%5Cfrac%7B4%7D%7B3%7D+-+%5Cfrac%7Bx%7D%7B6%7D+%5C%5C+++%5C%5C++%5Cfrac%7Bx%7D%7B2%7D%2B++%5Cfrac%7Bx%7D%7B6%7D%3D+%5Cfrac%7B4%7D%7B3%7D-++%5Cfrac%7B3%7D%7B5%7D+++%5C%5C++%5C%5C++%5Cfrac%7B8x%7D%7B12%7D%3D+%5Cfrac%7B20-9%7D%7B15%7D+%5C%5C++%5C%5C+%5Cboxed%7Bx%3D+%5Cfrac%7B11%7D%7B10%7D+++%7D%5C%5C++%5C%5C+)
![B) \\ \\ 2x- \frac{1}{5}=x+ \frac{4}{3}- \frac{7}{2} \\ \\ 2x-x= \frac{4}{3}- \frac{7}{2} + \frac{1}{5} \\ \\ x= \frac{40-105+6}{30} \\ \\ \boxed{x=- \frac{59}{30} }\\ \\ B) \\ \\ 2x- \frac{1}{5}=x+ \frac{4}{3}- \frac{7}{2} \\ \\ 2x-x= \frac{4}{3}- \frac{7}{2} + \frac{1}{5} \\ \\ x= \frac{40-105+6}{30} \\ \\ \boxed{x=- \frac{59}{30} }\\ \\](https://tex.z-dn.net/?f=B%29+%5C%5C++%5C%5C+2x-++%5Cfrac%7B1%7D%7B5%7D%3Dx%2B+%5Cfrac%7B4%7D%7B3%7D-++%5Cfrac%7B7%7D%7B2%7D++%5C%5C++%5C%5C+2x-x%3D+%5Cfrac%7B4%7D%7B3%7D-++%5Cfrac%7B7%7D%7B2%7D+%2B+%5Cfrac%7B1%7D%7B5%7D++++%5C%5C++%5C%5C+x%3D+%5Cfrac%7B40-105%2B6%7D%7B30%7D++%5C%5C++%5C%5C+%5Cboxed%7Bx%3D-+%5Cfrac%7B59%7D%7B30%7D++%7D%5C%5C++%5C%5C+)
![C) \\ \frac{x}{3}+ \frac{x}{5}+1= \frac{3x}{4}- \frac{1}{2} \\ \\ \frac{x}{3} + \frac{x}{5}- \frac{3x}{4}=- \frac{1}{2}-1 \\ \\ \frac{20x+12x-45x}{60}=- \frac{3}{2} \\ \\ - \frac{13x}{60}= -\frac{3}{2} \\ \\ \boxed{x= \frac{90}{13} }\\ \\ . C) \\ \frac{x}{3}+ \frac{x}{5}+1= \frac{3x}{4}- \frac{1}{2} \\ \\ \frac{x}{3} + \frac{x}{5}- \frac{3x}{4}=- \frac{1}{2}-1 \\ \\ \frac{20x+12x-45x}{60}=- \frac{3}{2} \\ \\ - \frac{13x}{60}= -\frac{3}{2} \\ \\ \boxed{x= \frac{90}{13} }\\ \\ .](https://tex.z-dn.net/?f=C%29+%5C%5C++%5Cfrac%7Bx%7D%7B3%7D%2B++%5Cfrac%7Bx%7D%7B5%7D%2B1%3D++%5Cfrac%7B3x%7D%7B4%7D-++%5Cfrac%7B1%7D%7B2%7D++%5C%5C++%5C%5C++%5Cfrac%7Bx%7D%7B3%7D+%2B+%5Cfrac%7Bx%7D%7B5%7D-+%5Cfrac%7B3x%7D%7B4%7D%3D-+%5Cfrac%7B1%7D%7B2%7D-1+%5C%5C++%5C%5C++%5Cfrac%7B20x%2B12x-45x%7D%7B60%7D%3D-+%5Cfrac%7B3%7D%7B2%7D+%5C%5C++%5C%5C+++-++%5Cfrac%7B13x%7D%7B60%7D%3D+-%5Cfrac%7B3%7D%7B2%7D++++++%5C%5C++%5C%5C+%5Cboxed%7Bx%3D+%5Cfrac%7B90%7D%7B13%7D+%7D%5C%5C++%5C%5C+.)
![D) \\ 2x-1- \frac{3x}{10}- \frac{2}{3}=2(x-3)+ \frac{1}{5} \\ \\ \frac{17x}{10}- \frac{5}{3}=2x-6+ \frac{1}{5} \\ \\ \frac{17x}{10}-2x=-6+ \frac{1}{5} + \frac{5}{3} \\ \\ - \frac{3x}{\not10}= \frac{-90+3+25}{\not15} \\ \\\boxed{ x= \frac{124}{9}} \\ \\ \\ D) \\ 2x-1- \frac{3x}{10}- \frac{2}{3}=2(x-3)+ \frac{1}{5} \\ \\ \frac{17x}{10}- \frac{5}{3}=2x-6+ \frac{1}{5} \\ \\ \frac{17x}{10}-2x=-6+ \frac{1}{5} + \frac{5}{3} \\ \\ - \frac{3x}{\not10}= \frac{-90+3+25}{\not15} \\ \\\boxed{ x= \frac{124}{9}} \\ \\ \\](https://tex.z-dn.net/?f=D%29+%5C%5C+2x-1-+%5Cfrac%7B3x%7D%7B10%7D-+%5Cfrac%7B2%7D%7B3%7D%3D2%28x-3%29%2B+%5Cfrac%7B1%7D%7B5%7D++%5C%5C++%5C%5C++%5Cfrac%7B17x%7D%7B10%7D-+%5Cfrac%7B5%7D%7B3%7D%3D2x-6%2B+%5Cfrac%7B1%7D%7B5%7D+++%5C%5C++%5C%5C++%5Cfrac%7B17x%7D%7B10%7D-2x%3D-6%2B+%5Cfrac%7B1%7D%7B5%7D+%2B+%5Cfrac%7B5%7D%7B3%7D++%5C%5C++%5C%5C+-+%5Cfrac%7B3x%7D%7B%5Cnot10%7D%3D+%5Cfrac%7B-90%2B3%2B25%7D%7B%5Cnot15%7D+++%5C%5C++%5C%5C%5Cboxed%7B+x%3D+++%5Cfrac%7B124%7D%7B9%7D%7D++++%5C%5C++%5C%5C++%5C%5C+)
Saludos!!
Saludos!!
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