Question

ayuda por favor con mi tarea de matemática es para hoy

Answer 1

 

$=\frac{\frac{x^2+3x+2}{x^2+6x+5}}{\frac{x^2-4}{x^2+3x+10}}\\= \frac{\left(x^2+3x+2\right)\left(x^2+3x+10\right)}{\left(x^2+6x+5\right)\left(x^2-4\right)}\\=\frac{\left(x+1\right)\left(x+2\right)\left(x^2+3x+10\right)}{\left(x^2+6x+5\right)\left(x^2-4\right)}\\=\frac{\left(x+1\right)\left(x+2\right)\left(x^2+3x+10\right)}{\left(x+1\right)\left(x+5\right)\left(x^2-4\right)}\\=\frac{\left(x+2\right)\left(x^2+3x+10\right)}{\left(x+5\right)\left(x^2-4\right)}\\....=\frac{x^2+3x+10}{x^2+3x-10}$