Question

Por favor, necesito ayuda con cualquier de los siguientes ejercicios!! Cualquiera, excepto el F y H!!! Ayudaaa!!!!! Sí me pueden pasar el calculo, se le agradecería!! Es re importante!!

Answer 1

Respuesta:

$\sqrt[3]{\frac{27}{1000} } - (\frac{14}{100}) ^{2} - (\frac{2}{100} )^{2} = \frac{3}{10} - \frac{49}{2500} -\frac{1}{2500} = \frac{750-49-1}{2500} = \frac{700}{2500} =\frac{7}{25} \\b) \frac{1}{6} . \frac{36}{100} : 3 + \frac{13}{20} = \frac{1}{50} + \frac{13}{20} = \frac{2+65}{100} = \frac{67}{100} \\c) (\frac{2}{10})^{2} + \frac{2}{5} - (\frac{5}{18} . \frac{18}{10} )^{2} = \frac{4}{100} + \frac{2}{5}- (\frac{1}{2})^{2} = \frac{4}{100}+ \frac{2}{5} - \frac{1}{4}= \frac{4+40-25}{100} = 19/100$

$d) \frac{5}{10} + \frac{1}{2} + \frac{4}{9} = \frac{1}{2} + \frac{1}{2} + \frac{4}{9} = 1+\frac{4}{9} = \frac{13}{9} \\e) (\sqrt[3]{8} + (\frac{4}{10})^{2} : \frac{24}{10} +2= (2+ \frac{4}{25} ): \frac{12}{5}+2 =\frac{9}{10} + 2 = \frac{29}{10}= 2,9$

$(\frac{8}{10} . \frac{27}{8} . \frac{1}{3} )- (\sqrt{\frac{4}{100}}+\sqrt{\frac{36}{100} }) = \frac{9}{10} -( \frac{2}{10} + \frac{6}{10} )^{2}= \frac{9}{10} - (\frac{4}{5})^{2} = \frac{9}{10} - \frac{16}{25} = \frac{45-32}{50} = \frac{13}{50}=0,26$