Question

ayudenme porfavor a resolver estas ecuaciones

Answer 1

(4/5)^6*(4/5)^2 = (4/5)^6+2 = (4/5)^8

((2/5)^3)/((2/5)^7) = (2/5)^3-7 = (2/5)^-4 = (5/2)^4

((-1/2)^3)^2 = (-1/2)^3*2 = (-1/2)^6

(5/2)^10*((5/4)^5)^-2 = (10/4)^10*(5/4)^-10