Question

a.-x^7/x^5
b.-6x^3y^2/2y
c.-21x^2y^3/7x^2y^2
d.-9a^2-6a/3a
e.-10a^3+8/2
f.-12a^2+8a+24/2

ayuda porfa con proceso​

Answer 1

Explicación paso a paso:

$\frac{ {x}^{7} }{ {x}^{5} } = {x}^{7 - 5} = {x}^{2}$

$\frac{ 6{x}^{3} {y}^{2} }{2y} = \frac{ 6 {x}^{3} {y}^{2 - 1} }{2} = 2 {x}^{3} {y}$

$\frac{ 21{x}^{2} {y}^{3} }{7 {x}^{2} {y}^{2} } = \frac{ 21 {x}^{2 - 2} {y}^{3 - 2} }{7} = 3{x}^{0} {y} = 3y$

$\frac{ 9{a}^{2} - 6a }{ 3a} = \frac{ 9 {a}^{2} }{3a} - \frac{6a}{3a} = 3 {a}^{2 - 1} - 2 {a}^{1 - 1} = 3a - 2 {a}^{0} = 3a - 2$

$\frac{10 {a}^{3} + 8 }{2} = \frac{10 {a}^{3} }{2} + \frac{8}{2} = 5 {a}^{3} + 4$

$\frac{12 {a}^{2} + 8a + 24 }{2} = \frac{12 {a}^{2} }{2} + \frac{8a}{2} + \frac{24}{2} = 6 {a}^{2} + 4a + 12$

Espero haberte ayudado, dame coronita, cinco estrellas y un gracias