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Adjuntos:

Respuestas

Respuesta dada por: huamanmalca
1

Explicación paso a paso:

Tenemos que:

A

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c | \ b

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B a C

a^2 + c^2 = b^2

1.

E = a*tgC + b*cosA

E = a*(c/a) + b*(c/b)

E = c + c

E = 2*c

2.

E = (b - a*senA)*cscC

E = (b - a*(a/b))*(b/c)

E = (b - a^2/b)*(b/c)

E = (b^2 - a^2)*(b/(b*c))

E = (b^2 - a^2)/c

E = (c^2)/c

E = c

3.

E = (tgA + tgC)*senA

E = (a/c + c/a)*(a/b)

E = (a^2 + c^2)*(a/(a*b*c))

E = (b^2)/(b*c)

E = b/c

E = csc c

4.

Aplicamos teorema de Pitagoras:

a^2 + c^2 = b^2

(x + 1)^2 + (x - 1)^2 = (2*√5)^2

x^2 + 2*x + 1 + x^2 - 2*x + 1 = 20

2*x^2 + 2 = 20

2*x^2 = 18

x^2 = 9

x = √9

x = 3

E = ctgθ + √5*cosθ

E = 4/2 + √5*(4/(2*√5))

E = 2 + 2

E = 4

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