Question

x^3 + y ^3 = 28 , ademas xy ( x+y ) = 12 calcula A = x+y

Answer 1

Respuesta:

A = x+y = 4

Explicación paso a paso:

$x^{3} +y^{3} =28$

$xy(x+y)=12$  $= x^{2} y+xy^{2}$

$calcular A = x+y$

$( x+y)^{3}$ $= x^{3} +3x^{2} y+3xy^{2} +y^{3}$

$( x+y)^{3}$ =  $x^{3} +y^{3} +3x^{2} y+3xy^{2}$

$( x+y)^{3}=x^{3} +y^{3} +3(x^{2} y+xy^{2})$

$( x+y)^{3}=28 +3(12)$

$( x+y)^{3}=28 +36$

$( x+y)^{3}=64$

$( x+y)=\sqrt[3]{64}$

$( x+y)=4$