Question

Ayudaaa $\sqrt[4]{4x+41} + 2 = 5$

Answer 1

$\sqrt[4]{4 \times + 41} + 2 = 5$

$\sqrt[4]{4 \times + 41} = 5 - 2$

$\sqrt[4]{4 \times + 41} = 3$

$4 \times + 41 = 81$

$4 \times = 81 - 41$

$4 \times = 40$

$\times = 10$

$\sqrt[4]{4 \times 10 + 41} + 2 = 5$

$5 = 5$

$\times = 10$