Question

$x^{2} +2X+5=0$
CALCULAR (x+5)(x+7)(x-3)(x-5)
ayudenn porfisSS

Answer 1

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${x}^{2} + 2x + 5 = 0 \\ {x}^{2} + 2x - 15 = - 20 \\ (x + 5)(x - 3) = - 20$

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${x}^{2} + 2x + 5 = 0 \\ {x}^{2} + 2x - 35 = - 40 \\ (x + 7)(x - 5) = - 40$

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$= (x + 5)(x + 7)(x - 3)(x - 5) \\ = (x + 5)(x - 3)(x + 7)(x - 5) \\ = (- 20)( - 40) \\ = 800$