Question

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Answer 1

P(x) = (x+3)^2 + (3x - 2)^20 + 3

P(1) = (1 +3)^2 + (3(1) - 2) ^20 + 3

P(1) = (4)^2 + (3 - 1) ^20 + 3

P(1) = 16 + (1)^20 + 3

P(1) = 16 + 1 + 3

P(1)= 20

Q(x) = nx^2 + 3x + 2

Q(2)= n(2)^2 + 3(2) + 2

Q(2) = 4n + 6 + 2

Q(2) = 4n + 8

P(1) = Q(2) , calcula "n"

20= 4n + 8

20 - 8 = 4n

12 = 4n

3=n