Question

2.- Reducir las siguientes expresiones: a) 3(2a-b)^2+2(a-2b)(a+2b)+(3b-a)(3b+a)-(3a-2b)^2

Answer 1

Respuesta:

Explicación paso a paso:

Respuesta =4$a^{2}$

$3(2a-b)^{2}+2(a-2b)(a+2b)(+3b-a)(3b+a)-(3a-2b)^{2}$

$3(4a^{2} -4ab+b^{2}) +2(a-2b)(a+2b)+(3b-a)-(9a^{2} -12ab+4b^{2} )$

$12a^{2} -12ab+3b^{2} +2(a-2b)(a+2b)+(3b-a)-(9a^{2} -12ab+4b^{2} )$$12a^{2} -12ab+3b^{2} +2a^{2}-8b^{2} +(3b-a)(3b+a)-(9a^{2} -12ab+4b^{2} )$$12a^{2} -12ab+3b^{2} +2a^{2}-8b^{2} +9b^{2}-a^{2} -(9a^{2} -12ab+4b^{2} )$$12a^{2} -12ab+3b^{2} +2a^{2}-8b^{2} +9b^{2}-a^{2} -9a^{2} +12ab-4b^{2}$

=$4a^{2}$